4th Year Lineman Apprentice Practice Exam

Question: 1 / 400

For a system voltage of 240, 3-phase with 150 amps and a power factor of 80%, what is the Kw power load?

50 Kw

To calculate the kilowatt (kW) power load for a three-phase system, you can use the formula:

\[ kW = \sqrt{3} \times V \times I \times PF \]

where:

- $ V $ is the line-to-line voltage (in volts),

- $ I $ is the current (in amps),

- $ PF $ is the power factor (as a decimal).

For this question:

- $ V = 240 $ volts

- $ I = 150 $ amps

- $ PF = 0.80 $

Plugging the values into the formula gives:

kW = \sqrt{3} \times 240 \times 150 \times 0.80

Calculating step-by-step:

1. Calculate $ \sqrt{3} $ which is approximately 1.732.

2. Now, multiplying this by the voltage:

- $ 1.732 \times 240 \approx 415.68 $

3. Next, multiply this result by the current:

- $ 415.68 \times 150 \approx 62352 $

4. Finally, apply the power factor:

75 Kw

60 Kw

45 Kw

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